My friend asked me how to create following SQL query:
For each employee hired before 1992, display the employee’s last name, hire date and calculate the number of YEARS between TODAY and the date the employee was hired. Label the column Years worked.
Order your results by the number of years employed.
Round the number of years up to the closest whole number.
I was trying to find the solution in the Net, but unfortunately found nothing that would help, that is why I decided to make this query by my one. It appeared to be very simple.
Here is the query:
TO_CHAR(ROUND((sysdate – hire_date)/365)) "Years Worked" 2 FROM EMPLOYEES 3 WHERE hire_date < ‘1-Jan-1992’ 4 ORDER BY "Years Worked" desc;
So first line selects employee last_name and hire_date, and also I created new column called Years Worked by getting the Date in number format (TO_CHAR) subtracting hire_date from the system date and dividing by 365 to find the value in year. If the year has 366 days it does not really matter because we are using ROUND function and it cuts all decimals. In line 3 WHERE clause checks if hire_Date is smaller than 1992.Last line orders everything by Years Worked column starting from the biggest amount of years worked.
That’s it, Have fun!
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Oracle support Mathematical Subtract ‘-‘ operator on Data datatype. You may directly put in select clause following statement:
to_char (s.last_upd – s.created, ‘999999D99’)
Further divide the result by 365 to calculate difference in Years.
For detailed example, you may refer a post available at – http://crackingsiebel.wordpress.com/2010/12/01/oracle-sql-date-difference-in-days/
Thank you for sharing your thoughts.
However, even if the example you are showing works fine, It looks very confusing, and person who will work on it after you, will be very annoyed with such code.
My code, on the other hand, is much more readable.
Regards,
Anatoly
THANK YOU!
Thank you very much ! It’s really easy readable and useful.
You rock, Anatoly ッ
The Round () function/utility is utilized to round a statist field to the digit of decimals defined.
http://www.inoracle.com/sql-round-function-oracle/
It helpful for me
could you please give an easy solution in oracle for this query
find the length of service of the employees (of the form n years and m months).
Find out the employee names and number of years worked along with their department names in descending order by number of years (up to two decimal points) worked.
You could also do something like this
select extract(year from (sysdate – hire_date) year to month) “Years Worked”
from employees
where hire_date < to_date('1-Jan-1992', 'dd-Mon-yyyy')
order by "Years Worked" desc;